问题已解决
单选题第三题,公式我知道是y=a+bx 就是最后求解的过程数是怎么得来的不懂
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你好需要计算做好了给你
2022 04/07 05:06
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84785011 ![](/wenda/_nuxt/img/reply1.d92ea43.png)
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2022 04/07 05:07
好的谢谢麻烦你了,那就等你做好了给我,我好研究
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暖暖老师 ![](/wenda/_nuxt/img/reply2.28c7604.png)
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2022 04/07 05:18
两个方程相减得50=50Xb
得b=1
带入任何一个求得a
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84785011 ![](/wenda/_nuxt/img/reply1.d92ea43.png)
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2022 04/07 05:20
你把两个方程相减的过程给我呗,你这样高度概括我看不懂
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84785011 ![](/wenda/_nuxt/img/reply1.d92ea43.png)
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2022 04/07 05:26
不用了我明白了谢谢
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暖暖老师 ![](/wenda/_nuxt/img/reply2.28c7604.png)
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2022 04/07 05:29
250=a+100b
300=a+150b
300-250=a-a+150b-100b
整理后就是50=50b这样可明白了